Question

find the root of x2+x-6=0​

Answer 1

Answer:

${x}^{2} + x - 6 = 0$

${x}^{2} + (3 - 2)x - 6 = 0$

${x}^{2} + 3x - 2x - 6 = 0$

$x(x + 3) - 2(x + 3) = 0$

$(x + 3)(x - 2) = 0$

$x = - 3 \: \: \: \: or \: \: \: x = 2$

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Answer 2

x² + x - 6 =0

therefore

x= 2,-3

as +3 × -2 = -6

and +3-2= +1

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