find the root(s) of 2x[3x-1/2]=
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x=0
x=1/6......is the right answer
x=1/6......is the right answer
alviyarizwan10:
can you show the method
2x=0 x=0
mark me as brainlieast
ok
Answered by
0
2x[3x-1/2]
=2(3x - 0.5)
=6x-1
=2(3x - 0.5)
=6x-1
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