Math, asked by alviyarizwan10, 1 year ago

find the root(s) of 2x[3x-1/2]=

Answers

Answered by adityakr495p0lxk1

1

x=0
x=1/6......is the right answer

alviyarizwan10: can you show the method

adityakr495p0lxk1: 2x=0 x=0

adityakr495p0lxk1: mark me as brainlieast

alviyarizwan10: ok

Answered by AryanTennyson

0

2x[3x-1/2]
=2(3x - 0.5)
=6x-1

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