Question

Find the root Square the numbers
repeating subraction method
(0) 144
256
(iii) 484
(IV) 4761
ران​

Answer 1

Answer:

Step-by-step explanation:

(i)

=144-1________1

=143-3_________2

=140-5_________3

=135-7__________4

=128-9_________5

=119-11__________6

=108-13__________7

=95-15__________8

=80-17___________9

=63-19___________10

=44-21___________11

=23-23__________12

=0

Therefore we conclude that root 144=12

Step 1: 256 - 1 = 255

/* Subtracting of first odd number */

Step 2: 255 - 3 = 252

/* Subtracting of second odd number */

Step 3: 252 - 5 = 247

/* Subtracting of Third odd number */

Step 4: 247 - 7 = 240

Step 5: 240 - 9 = 231

Step 6: 231 - 11 = 220

Step 7: 220 - 13 = 207

Step 8: 207 - 15 = 192

Step 9: 192 - 17 = 175

Step 10: 175 - 19 = 156

Step 11: 156 - 21= 135

Step 12: 135 - 23 = 112

Step 13: 112 - 25 = 87

Step 14: 87 - 27 = 60

Step 15: 60 - 29 = 31

Step 16: 31 - 31 = 0

From 256,we have subtracted 16 successive odd numbers starting from 1 and obtained zero (0) at 16 th step.

Therefore, we conclude that root 256=16

484−1=483

483−3=480

480−5=475

468−9=459

459−11=448

448−13=435

435−15=420

420−17=403

403−19=384

384−21=363

363−23=340

340−25=315

315−27=288

288−29=259

259−31=228

228−33=195

195−35=160

160−37=123

123−39=84

84−41=43

43−43=0

In this case, we had to subtract in 22 steps to get to 0. Hence, root of 484 is 22.

4761-1=4760_______1

4760-3=4757_______2

4757-5=4752________3

4752-7=4745________4

4745-9=4736_________5

.......=0_______________69

Therefore we conclude that root 4761=69