Question

find the rootof the following quadratic equation exist by completing the sqare x2 -10x-2=0​

Answer 1

Answer:

5 ± 3√3

Step-by-step explanation:

⇒ x^2 - 10x - 2 = 0

  Divide by the coefficient of x^2,  here it is 1,

⇒ x^2 - 10x - 2 = 0

⇒ x^2 - 2(5x) = 2

  Add the square of 1/2 of term with x, means to add (5)²

⇒ x^2 - 2(5x) + 5² = 2 + 5²

⇒ (x - 5)² = 2 + 25 = 27

⇒ x - 5 = √27 = ±3√3

⇒ x = 5 ± 3√3