find the roots
2x²+x-6=0
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2x²+x-6 = 0
=> 2x²+4x-3x-6
=> 2x(X+2)-3(x+2)
=> (x+2)(2x-3)
=> X = -2,3/2
Answered by
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Answer:
2x²+x-6=0
2x²+4x-3x-6=0
2x(x+2) -3(x+2) =0
(x+2) (2x-3) =0
so x=-2, 3/2 are the roots
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