Question

Find the roots 4X^2-4Px+p^2-Q^2

Answer 1

Answer:

For the given quadratic equation,

a=4,b=−4p and c=p

2

−q

2

Thus, x=

2a

−b±

b

2

−4ac

=

2×4

−(−4p)±

(−4p)

2

−4×4×(p

2

−q

2

)

=

8

4p±

16p

2

−16p

2

+16q

2

=

8

4p±4q

=

2

p±q

So, the roots of the quadratic equation are :

2

p+q

and

2

p−q