Question

find the roots by factorization
2x*2-4x+16​

Answer 1

Answer:

2x^2-4x+16

2x^2-8x+4x+16

2x(x-4)+4(x-4)

(2x+4)(x-4)

Answer 2

Answer:

2 and 4

Step-by-step explanation:

2x²-4x+16=0

No roots possible, I think you made an error while typing the question

I think your question was this=>2x²-4x-16=0

2x²-4x-16=0

2x²-8x+4x-16=0

2x(x-4)+4(x-4)=0

(2x+4)(x-4)=0

Either 2x+4=0=>x=2

or x-4=0=>x=4

Roots= 2 and 4