Question

Find the roots by factorization 2x^+2-6=0

Answer 1

Step-by-step explanation:

Question is incomplete.....correct the question....

Solution :

Given Quadratic equation (may this question is write)

2x² + x - 6 = 0

Splitting the middle term , we get

2x² + 4x -3x - 6 = 0

=> 2x( x + 2 ) - 3( x + 2 ) = 0

=> ( x + 2 )( 2x - 3 ) = 0

Therefore ,

x + 2 = 0 or 2x - 3 = 0

x = -2 or x = 3/2

hope its helpful for you......✔✔✔

Answer 2

Answer:

$2x^{2}+2-6=0\\ 2x^{2}-4= 0\\2x^{2}=4\\x^{2}=2\\x=\sqrt{2}$

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