Question

find the roots by factorization
${2x}^{2} + x - 6 = 0$
​

Answer 1

Answer:

-2, 3/2

Step-by-step explanation:

2x^2 + x-6=0

2x^2 + 4x - 3x - 6 = 0

2x(x+2) -3(X+2) = 0

(2x-3) (X+2) =0

(2x-3) = 0 (X+2) =0

2x = 3 X = -2

X=3/2

Answer 2

Answer:

-2,3/2

Step-by-step explanation:

2x^2+x-6=0

or, (2x-3)(x+2)=0

x= -2; 3/2