Question

find the roots by quadratic formula 4x^+6x+2=0​

Answer 1

Answer:

$- \frac{10}{8} \: and \: - \frac{2}{8}$

Step-by-step explanation:

Using Shridhracharya formula

$x=\frac{ - b \pm\sqrt{{b}^{2} - 4ac} }{2a}$

$x= \frac{ - 6 \pm \: \sqrt{ {6}^{2} - 4 \times 4 \times 2} }{2 \times 4}$

$x=\frac{ - 6 \pm \sqrt{36 - 32} }{8}$

$x = \frac{ - 6 \pm \sqrt{4} }{8}$

$x = \frac{ - 6 - 4}{8} , \frac{ - 6 + 4}{8}$

$x = - \frac{10}{8} , \frac{ - 2}{8}$

Hence the roots are $- \frac{10}{8} \: and \: - \frac{2}{8}$