Find the roots by quadratic formula: 4y^2+4by-(a^2-b^2 )=0
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★ QuestioN :
Find the roots by quadratic formula :
4y² + 4by - (a² – b² ) = 0
GIVEN :
- 4y² + 4by – ( a² + b² ) = 0
TO FIND :
- The given roots by quadratic formula, when the informations are given = ?
SolutioN :
→ 4y² + 4by – ( a² + b² ) = 0 ( GIVEN )
→ Formula ( quadratic formula ) = x = -b + √b² – 4ac / 2a
( substituting the same formula as per the question asked )
→ y = -4y + √ (4b)² – 4×4 × (a² + b²) / 2 × 4
→ y = -4b + √16b² (a² + b²) / 2 × 4
→ y = -4b + √16b² + 16a² – 16b² / 8
→ y = -4b + √16a² / 8
→ y = -4b – 4a /8
→ y = 4 (b + a) / 8
→ y = a + b / 2
→ y = -4b + 4a /8
→ y = 4a – 4b /8
→ y = 4 (a-b) /8
→ y = a - b / 2
So, Therefore, The value of y = a + b and a - b /2
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