Find the roots by quadratic formula if they exist (2x-1)(x-3)=(x+5)(x-1)
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Step-by-step explanation:
-2x-3x =5x-1
-5x=4x
-5x - 4x
9x
Answered by
0
Step-by-step explanation:
We know that the general form of quadratic equation is ax
2 +bx+c=0.
The given equation is (2x−1)(x−3)=(x+5)(x−1) can be simplified as follows:
(2x−1)(x−3)=(x+5)(x−1)
⇒2x(x−3)−1(x−3)=x(x−1)+5(x−1)
⇒2x 2 −6x−x+3=x 2 −x+5x−5
⇒2x 2−7x+3=x 2 +4x−5
⇒2x 2 −7x+3−x 2−4x+5=0
⇒x 2−11x+8=0
Since the equation x
2−11x+8=0 is of the form ax 2 +bx+c=0.
Hence, the equation
(2x−1)(x−3)=(x+5)(x−1) is a quadratic equation.
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