Question

find the roots by section formula
2xsq-2√2x+1=0​

Answer 1

Step-by-step explanation:

the answer is in the attachment

Answer 2

2x² - 2√2x + 1 = 0

2x² - √2x - √2x + 1 = 0

√2x ( √2x - 1 ) - 1 ( √2x - 1 ) = 0

( √2x - 1 ) ( √2x - 1 ) = 0

* ( √2x - 1 ) = 0

x = 1/√2

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