find the roots for the equation Kx(x-2)+6=0 is equal to zero
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Answer:
the given equation can be written in the form of
k {x}^{2} - 2kx + 6 = 0kx
2
−2kx+6=0
now it has equal roots that means The Discriminant is 0
D = 0
Also
\begin{lgathered}{b}^{2} - 4ac = 0 \\ {4k}^{2} - 4(k)(6) = 0 \\ 4 {k}^{2} - 24k = 0 \\ 4k(k - 6) = 0 \\ k - 6 = 0 \\ k = 6\end{lgathered}
b
2
−4ac=0
4k
2
−4(k)(6)=0
4k
2
−24k=0
4k(k−6)=0
k−6=0
k=6
Hence the value of K is 6.
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