Question

find the roots of 15x squre -10root6x+10=0​

Answer 1

Answer:

(root2/3),(root2/3)

Step-by-step explanation:

D=b^2-4ac

=(-10root6)^2-4*15*10

=600-600=0

x=-b+-rootD/2a

=10root6+-root0/30

=10root6/30

=(root6)/3

=root(2/3)

therefore roots are equal that is (root2/3),(root2/3)