find the roots of 2π2 -5π+7=0
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x = {5 ± i√31} / 4
Step-by-step explanation:
Q) find the roots of 2π2 -5π+7=0
⇒ Given equation is 2π² - 5π + 7 = 0
put the π = x
∴ 2x² - 5x + 7 = 0
we know the formula for finding x from equation ax² + bx + c = 0 is
x = [-b ± √(b²-4ac)] / 2a
∵ a=2, b= -5, c=7
x = {-(-5) ± √[(-5)²-4*2*7]} / 2*2
= {5 ± √[25-56]} / 4
= {5 ± √[-31]} / 4
= {5 ± √[31*(-1)]} / 4
x = {5 ± i√31} / 4
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