find the roots of 2/x^2-5/x+2=0
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Answered by
182
2/x^2 - 5/x + 2 = 0
[multiply both sides with x^2]
2 - 5x +2x^2 = 0
2x^2 -4x -x +2 =0
2x(x-2) -(x-2) =0
(x-2)(2x-1)=0
x= 2, 1/2
[multiply both sides with x^2]
2 - 5x +2x^2 = 0
2x^2 -4x -x +2 =0
2x(x-2) -(x-2) =0
(x-2)(2x-1)=0
x= 2, 1/2
Answered by
80
2/x^2-5x+2=0
multiply by x^2 we get
2-5x+2x^2=0
2x^2-5x+2=0
2x^2-4x-1x+2=0
2x(x-2)-1(x-2)=0
(2x-1)(x-2)=0
2x-1=0 or x-2=0
2x=1 or x=2
x=1/2 or x=2
multiply by x^2 we get
2-5x+2x^2=0
2x^2-5x+2=0
2x^2-4x-1x+2=0
2x(x-2)-1(x-2)=0
(2x-1)(x-2)=0
2x-1=0 or x-2=0
2x=1 or x=2
x=1/2 or x=2
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