find the roots of 2 x² + 6 = 7x
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Answered by
2
2x²+6 = 7x
=> 2x²-7x+6 = 0
=> 2x²-(4x+3x)+6 = 0
=> 2x²-4x-3x+6 = 0
=> 2x(x-2)-3(x-2) = 0
=> (x-2)(2x-3) = 0
=> either x = 2 or 3/2
Answered by
3
Answer:
The roots of the equation 2x²+6=7x are (3/2) & 2.
Step-by-step explanation:
2x²-7x+6=0
2x²+(-4x)+(-3x)+6=0 [Splitting the middle term]
2x(x-2)-3(x-2)=0
(2x-3)(x-2)=0
2x-3=0 , x-2 = 0
x=3/2 , x=2
Hope you understood ! ☺
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