Question

find the roots of 2x^+5√3x+6 by using the quadratic formula​

Answer 1

Answer:

Hence real roots exist.

x = -√3/2, x= -2√3.

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Answer 2

Answer:

x= -√3/2 , x= -2√3

Step-by-step explanation:

2x^2+5√3x + 6 using quadratic formula

b^2 -4ac > or = 0

(5√3)^2 - 4×2×6

25×3-48 = 75-48

75-48= 27

27>0

so the quadratic equation has real roots

now finding the roots

splitting the middle tems

2x^2+5√3x+6 =0

2x^2+4√3x+6. =0

2x (x + 2√3) + √3 (x+2√3) =0

(2x+√3) +( x+2√3) =0

2x+√3 = 0

2x = -√3 => x = -√3/2

x+2√3=0

x = -2√3

therefore x= -√3/2

x= -2√3