find the roots of 2x sqare-7x+3=0, by the method of completing the sqaure
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2x²-7x+3=0
x²-7x/2+3/2=0
x²-2(7/4)x+(7/4)²=(7/4)²-3/2
(x-7/4)²=(49/16)-(3/2)
=(49-24)/16
=25/16
=>x-7/4=5/4;-5/4
=>x=12/4;2/4
=3;1/2
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