Question

find the roots of 2x square-7x+6=0 by method of completing square

Answer 1

2x^2-7x+6=0
x^2-7x/2+3=0
x^2-7x/2+(49/16)-(49/16)+3=0
[x-(7/4)]^2-(49/16)+3=0
[x-7/4]^2-(1/16)=0
[x-7/4]^2=1/16
x-7/4=1/4 OR x-7/4=-1/4
x=2 OR x=3/2

Answer 2

Hope it's useful . Mark as the brainliest answer.