find the roots of 2x² - 3(a+b)x + a² + 2ab + b² =0
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Answered by
1
Answer:
x = (a + b), (a + b) /2
Step-by-step explanation:
Given 2x² - 3(a+b)x + a² + 2ab + b² = 0
= 2x² - 3(a+b)x + (a + b) ² =0
=> x = [3(a + b) +, - sq( 9(a + b) ² - 8(a + b) ²)]/4
=> x = [3(a + b) +, - sq(a + b)²]/4
=> x = 2(a + b)/4, 4(a + b) /4
=> x = (a + b), (a + b) /2
Answered by
1
Answer:
Answer:
x = (a + b), (a + b) /2
Given 2x² - 3(a+b)x + a² + 2ab + b² = 0
= 2x² - 3(a+b)x + (a + b) ² =0
=> x = [3(a + b) +, - sq( 9(a + b) ² - 8(a + b) ²)]/4
=> x = [3(a + b) +, - sq(a + b)²]/4
=> x = 2(a + b)/4, 4(a + b) /4
=> x = (a + b), (a + b) /2
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