Question

Find the roots of: √2x²+7x+5√2=0
​

Answer 1

√2x² + 7x + 5√2 = 0

√2x² + 5x + 2x + 5√2 = 0

x(√2x + 5) + √2(√2x + 5) = 0

(x + √2) (√2 + 5) = 0

x + √2 = 0 ; √2x + 5 = 0

x = -√2 ; √2x = -5

x = -√2 ; x = -5/√2

Hence , the roots are x = -√2 and

x = -5/√2

Answer 2

Answer:

√2x^2+2x+5x+5√2=0

=x(√2x+2)+√2(√2x+5)

=(x+√2)=0 ,(√2x+5)=0. x=-√2,x=-5/√2

Step-by-step explanation:

Therefore,the value of x=-√2 and x=-5/√2