Question

Find the roots of: 36 x 2 – 12a x + (a 2 – b 2 )

Answer 1

Answer:

36x²-12ax+(a²-b²)=0

b²-4ac

144a²-4(36)(a²-b²)=0

144a²- 144a²+144b²=0

144b²

by formula method

x=12a±root144b²/72

x=12a±12b/72

x=12(a+b)/72

x=4(a+b)/18

x=2(a+b)/9

x=2(a-b) /9 is the answer of this question