Math, asked by vsrilayaa, 1 year ago

Find the roots of 3x^2 + 2sqrt5x - 5 = 0

Answers

Answered by hukam0685
1

3 {x}^{2}  + 2 \sqrt{5} x - 5 = 0 \\ 3 {x}^{2}  + 3 \sqrt{5}x -  \sqrt{5} x - 5 = 0 \\ 3x(x +  \sqrt{5}) -  \sqrt{5} (x +  \sqrt{5}) = 0 \\ (3x -  \sqrt{5}  )(x +  \sqrt{5}) = 0 \\ roots \: are \\ 3x -  \sqrt{5}   = 0 \\ x =  \frac{ \sqrt{5} }{3}   \\ x +  \sqrt{5}  = 0 \\ x =  -  \sqrt{5}
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