Question

find the roots of
3x²+2x+5= 0 if
they
exist.
of​

Answer 1

Step-by-step explanation:

The nature of the roots is unequal and not real i.e. imaginary roots.

Step-by-step explanation:

Given : Quadratic equation 3x^2 + 2x+5= 03x2+2x+5=0

To find : The nature of quadratic equation ?

Solution :

The nature of the quadratic equation is determined by discriminant.

1) D=b^2-4ac=0D=b2−4ac=0 then roots are real and equal

2) D=b^2-4ac > 0D=b2−4ac>0 then roots are real and unequal.

3) D=b^2-4ac < 0D=b2−4ac<0 then roots are unequal and not real i.e. imaginary.

In 3x^2 + 2x+5= 03x2+2x+5=0 a=3, b=2 and c=5

Substitute the value in discriminant,

D=(2)^2-4(3)(5)D=(2)2−4(3)(5)

D=4-60D=4−60

D=-56D=−56

D < 0D<0

The nature of the roots is unequal and not real i.e. imaginary roots.

Answer 2

Answer:

Step-by-step explanation: