find the roots of 3x2+6x=0
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Answered by
0
Answer:
HEY HERE IS YOUR ANSWER
It is wrong question
Correct question is =>
3 {x}^{2} - 5x + 2 = 03x
2
−5x+2=0
So i am taking the equation as the above
3 {x}^{2} - 5x + 2 = 03x
2
−5x+2=0
= > 3 {x}^{2} - 3x - 2x + 2 = 0=>3x
2
−3x−2x+2=0
= > 3x(x - 1) - 2(x - 1) = 0=>3x(x−1)−2(x−1)=0
= > (3x - 2)(x - 1) = 0=>(3x−2)(x−1)=0
Thus,
➡️ x-1 = 0
➡️ x =0
And 3x-2 =0
➡️ 3x =2
➡️ x = 3/2
____________________
Hope it will help you
Answered by
0
Step-by-step explanation:
3x2+6x=0
x²+2x=0
x(x+2)=0
x=0 or x=-2
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