Math, asked by dhaliwa168, 2 days ago

find the roots of 3x2+6x=0​

Answers

Answered by jeenasarajoseph27
0

Answer:

HEY HERE IS YOUR ANSWER

It is wrong question

Correct question is =>

3 {x}^{2} - 5x + 2 = 03x

2

−5x+2=0

So i am taking the equation as the above

3 {x}^{2} - 5x + 2 = 03x

2

−5x+2=0

= > 3 {x}^{2} - 3x - 2x + 2 = 0=>3x

2

−3x−2x+2=0

= > 3x(x - 1) - 2(x - 1) = 0=>3x(x−1)−2(x−1)=0

= > (3x - 2)(x - 1) = 0=>(3x−2)(x−1)=0

Thus,

➡️ x-1 = 0

➡️ x =0

And 3x-2 =0

➡️ 3x =2

➡️ x = 3/2

____________________

Hope it will help you

Answered by priyackhanapure
0

Step-by-step explanation:

3x2+6x=0

x²+2x=0

x(x+2)=0

x=0 or x=-2

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