Question

Find the roots of 4x^2+3x+5=0by the method of completing the Square

Answer 1

Step-by-step explanation:

4x² + 3x + 5 = 0

dividing bu 4,

4x²/ 4+ 3x/4+5/4=0

x²+3x /4+5/4 = 0

we know that,

( a+b)² = a²+ 2ab+ b²

Here, a= x &

2ab= 3x/4

2×b=2x/4........( as, a= x)

2b= 3/4

b=3/4×1/2

b= 3/81

Now,in our equation,

x²+ 3x/ 4+ 5/4=0

Adding and subtracting (3/8)²

x²+ 3x/4 + 5/4 + (3/8)² - (3/8)²

x²+ 3x/5 + (3/8)² + (5/4) - (3/8)² = 0

(x+3/8)² + 5/4 - (3/8)² = 0

(x+3/8)² = (3/8)² - 5/4

(x+3/8)² = 9/64 - 5/4

(x+3/8)² = 9 - (16) / 64

(x+3/8)² = 9 - 80 /64

(x+3/8)² = -17/64

Since square of any number cannot be negative.

So, answer does not exist....

Make as breilient answer...

Thanks.....

Answer 2

Answer:

Here the ans. doesn't exit...