Question

find the roots of 4x^2 - 4root3x + 3


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Answer 1

Answer:

x = √3 / 2 , √3 / 2

Step-by-step explanation:

4x^2 - 4 √3x + 3

b^2 - 4ac ( b = -4√3, a = 4, c = 3 )

so, (-4√3)^2 - 4(4)(3)

= 48 - 48 = 0

therefore, the equation has two equal roots

x = +_ b +_ √b^2 - 4ac / 2a

x = 4√3 +- √0 / 2(4)

x = 4√3 / 8

x = √3 / 2

hence, roots of the given quadratic equation is

x = √3 / 2 , √3 / 2