Question

find the roots of 5t^2-22t+41​

Answer 1

Answer:

No real roots.

Step-by-step explanation:

Q.E = 5t² - 22t + 41

⇒ 5t² - 22t + 41 = 0

Quadratic formula = $\frac{-b+-\sqrt{b^2-4ac} }{2a}$

a = 5 , b = -22 , c = 41

On sub. in quadratic formula we get

= $\frac{-(-22)+-\sqrt{(-22)^2-4(5)(41) } }{2(5)}$

= $\frac{22+-\sqrt{484-820} }{10}$

= $\frac{22+-\sqrt{-336} }{10}$

As the number under root is < 0.

So no real roots exist for 5t² - 22t + 41