Question

FIND THE ROOTS OF (5z + 2a)(3z +4b) = 8ab by completing the square........

Answer 1

$(5z + 2a)(3z +4b) = 8ab \\ \\ 15 {z}^{2} + 6az + 20bz + 8ab = 8ab \\ \\ 15 {z}^{2} + (6a + 20b)z = 8ab - 8ab \\ \\ 15 {z}^{2} + (6a + 20b)z = 0 \\ \\ (z)(15z + 6a + 20b) = 0 \\ \\ 1. \: \: z = 0 \\ \\ 2. \: \: 15z + 6a + 20b = 0 \\ \\ 15z = - (6a + 20b) \\ \\ z = - \frac{ (6a + 20b) }{15} \\ \\ \boxed{z = 0 \: \: and \: \: - \frac{ (6a + 20b) }{15}}$

Answer 2

Here’s your answer

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