Question

Find the roots of 6root5x^2-9x-3root5=0

Answer 1

6√5x² - 9x - 3√5 = 0

=> 6√5x² + 6x - 15x - 3√5 = 0

=> 6x(√5x + 1) -3√5( √5x+ 1) = 0

=> (√5x+1)(6x-3√5) = 0

Therefore,

Roots are -1/√5 and √5/2

Answer 2

Step-by-step explanation:

6√5x² - 9x - 3√5 = 0

6√5x² - 15x + 6x - 3√5= 0

3√5x(2x-√ 5) + 3(2x - √5) = 0

(3√5x + 3) ( 2x- √5) = 0

Either,

3√5x + 3 = 0

3√5x = -3

x= -3/3√5

x= -1/√5

or,

2x - √5 = 0

2x = √5

x = √5/2

Hence,

x = ( -1/√5, √5 /2 ) answer