Question

Find the roots of 6x^2-√2x-2=0 by the factorisation of the corresponding quadratic polynomial​

Answer 1

Answer:

$x = \frac{ - 2}{3 \sqrt{2} } \: or \: x = \frac{1}{ \sqrt{2} }$

Step-by-step explanation:

$6 {x}^{2} - \sqrt{2} x - 2 = 0 \\ 6 {x}^{2} - 3 \sqrt{2}x + 2 \sqrt{2}x - 2 = 0 \\ 3 \sqrt{2} x( \sqrt{2} x - 1) + 2( \sqrt{2} x - 1) = 0 \\ (3 \sqrt{2} x + 2)(\sqrt{2} x - 1) = 0 \\3 \sqrt{2} x + 2 = 0 \: or \: \sqrt{2} x - 1 = 0 \\ 3 \sqrt{2} x = - 2 \: or \: \sqrt{2} x = 1 \\ x = \frac{ - 2}{3 \sqrt{2} } \: or \: x = \frac{1}{ \sqrt{2} }$