Question

Find the roots of 6x square - root 2x - 2=0 by the factorisation method

Answer 1

$6 {x}^{2} - \sqrt{2} x - 2 = 0 \\6 {x}^{2} - 3 \sqrt{2}x + 2 \sqrt{2} x - 2 = 0 \\ 3x (2x - \sqrt{2}) + \sqrt{2} (2x - \sqrt{2} ) = 0 \\ (3x + \sqrt{2}) (2x - \sqrt{2} ) = 0 \\ 3x + \sqrt{2} = 0 \\ 3x = - \sqrt{2} \\ x = \frac{ - \sqrt{3} }{2} \\ 2x - \sqrt{2} = 0 \\ 2x = \sqrt{2} \\ x = \frac{ \sqrt{2} }{2} = \frac{1}{ \sqrt{2} }$

Answer 2

bihari sale Kya krega of k