Question

find the roots of 6x² - √2x - 2=0 by factorization

Answer 1

6x²-√2x-2=0
6x²-3√2x+2√2x-2=0
3√2x(√2x-1)+2(√2x-1)=0
(3√2x+2)(√2x-1)=0
so,
x=-2/3√2=-√2/3
and,
x=1/√2=√2/2
hope it helped you.....

Answer 2

X=-b+-√(b^2-4ac)/2a
x=√2+-√(2+48)/12
x=√2+-√50/12
x=√2+-5√2/12
x=√2+5√2/12. ,x=√2-5√2/12
X=6√2/12=1/√2. ,x=-4√2/12=-√2/3