Question

FIND THE ROOTS OF 6X² + 4 =0 BY APPLYING THE QUADRATIC FORMULA.​

Answer 1

No real roots occur...

Answer 2

Step-by-step explanation:

By comparing

$6 {x}^{2} + 4 = 0$

with

$a {x}^{2} + bx + c$

A=6

B=0

C=4

D=b2-4ac

=0-4*4*6

=(-96)

Since the discriminant is negative, there will be no real roots for this equation