find the roots of 7 x square + X - 8 =
0
Attachments:
Answers
Answered by
1
7x+(8-7)x-8
7x+8x-7x+56
x(7+8)-7(x+8)
(x-7)(x+8)
so,x=7
x=-8.....hope it help u
7x+8x-7x+56
x(7+8)-7(x+8)
(x-7)(x+8)
so,x=7
x=-8.....hope it help u
jaypatel725:
i think ur answer is incorrect
may be
how it is incorrect bro..
plz check it by putting value of x in equation
put value of x in given equation and check it
Answered by
1
7x^2+x-8=0
7x^2-7x+8x-8=0
7x(x-1)+8(x-1)=0
7x+8=0 or x-1=0
therefore x=-8/7 or x=1
7x^2-7x+8x-8=0
7x(x-1)+8(x-1)=0
7x+8=0 or x-1=0
therefore x=-8/7 or x=1
Similar questions