Question

Find the roots of a quadratic equation 2x2+3x-5=0.

Explain in steps please
Don't write direct answers ​

Answer 1

Answer:

x=1 and x= -5/2

Step-by-step explanation:

2x²+3x-5=0

2x²-2x+5x-5=0

2x(x-1)+5(x-1)=0

(x-1)(2x+5)=0

•°• x=1;x=-5/2

Hope it helps.......

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Answer 2

2x^2+3x-5

2x^2-2x+5x-5

2x(x-1)+5(x-1)

(2x+5)(x-1)

2x+5=0

x=-5/2

x-1=0

x=1.

x=1 and -5/2