Question

find the roots of a quadratic equation 9x^2 -9(a-b)x+( 2a^2+ 5ab+2b^2)=0

Answer 1

$9 {x}^{2} - 9(a - b)x + (2 {a}^{2} + 5ab + 2 {b}^{2} ) = 0 \\ 9 {x}^{2} - 9ax + 9bx + 2 {a}^{2} + 5ab + 2 {b}^{2} = 0 \\ 9x(x - a) + b(9x + 2b) + a(2a + 5b) = 0 \\ (x - a + 9x + 2b + 2a + 5b)(9x + b + a) = 0 \\ (10x + a + 7b) = 0 \\ x = - \frac{(a + 7b)}{10 } \\ 9x + a+ b = 0 \\ x = - \frac{(a + b)}{9}$
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