Question

Find the roots of an equation, a(3a-2)-1=0 by factorisation method.​

Answer 1

Answer:

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Step-by-step explanation:

Factoring  3a2-2a-1  

The first term is,  3a2  its coefficient is  3 .

The middle term is,  -2a  its coefficient is  -2 .

The last term, "the constant", is  -1  

Step-1 : Multiply the coefficient of the first term by the constant   3 • -1 = -3  

Step-2 : Find two factors of  -3  whose sum equals the coefficient of the middle term, which is   -2 .

     -3    +    1    =    -2    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -3  and  1  

                    3a2 - 3a + 1a - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   3a • (a-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (a-1)

Step-5 : Add up the four terms of step 4 :

                   (3a+1)  •  (a-1)

            Which is the desired factorization