Question

find the roots of equation 2×^2-5×+3=0by factorisation​

Answer 1

Answer:

$\Large \boxed{X=1, X=\frac{3}{2} }$

Step-by-step explanation:

Given:

2x²-5x+3=0

To solve this problem, first you have to isolate by the x from left to right numbers.

Solutions:

First solve with quadratic equation formula.

$\Large\boxed{\textnormal{REMEMBER USED QUADRATIC EQUATION FORMULA}}$

$\displaystyle \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Factor it out.

$\displaystyle 2x^2-5x+3=(x-1)(2x-3)$

Used zero factor principle formula.

$\Large\boxed{\textnormal{ZERO FACTOR PRINCIPLE FORMULA}}$

$\displaystyle AB=0, \quad A=0, \quad B=0 \quad (A=0, \quad B=0)$

Solve.

$\displaystyle x-1=0$

Add 1 from both sides.

$\displaystyle x-1+1=0+1$

Add numbers from left to right.

$\displaystyle 0+1=\boxed{1}$

$\Large\boxed{X=1}$

Solve.

$\displaystyle 2x-3=0$

Add 3 from both sides.

$\displaystyle 2x-3+3=0+3$

Solve.

Add.

$\displaystyle 0+3=3$

$\displaystyle 2x=3$

Divide by 2 from both sides.

$\displaystyle \frac{2x}{2}=\frac{3}{2}$

Solve.

$\Large\boxed{X=\frac{3}{2}}$

Hence, the final answer is x=1 and x=3/2.