find the roots of equation 3a^2x^2+8abx+4b^2=0
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Dear friend!!
3a sq x sq + 8abx +4b sq=0
3a sq x sq + 6abx +2 abx + 4b sq=0
3ax(ax + 2b)+2b(ax+2b)=0
(3ax +2b)(ax+ 2b)=0
x = -2b/3a,-2b/a ans
Hope it helps u
3a sq x sq + 8abx +4b sq=0
3a sq x sq + 6abx +2 abx + 4b sq=0
3ax(ax + 2b)+2b(ax+2b)=0
(3ax +2b)(ax+ 2b)=0
x = -2b/3a,-2b/a ans
Hope it helps u
Anonymous:
where is it??
let me type here
yh sure
if the polynomial 6x^4+8x^3-5x^2+ax+b is divided by another polynomial 2x^2-5, the remainder comes out to be zero, find a and b
ok i hv some imp work ill tell u ans in 2 hour ok
hmm... okay fine
hey dear ur ques has been solved!
direct value btau ki u need whole solution...?
solution plzz
kasa du comment m?
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