Question

find the roots of equation
3x² + 4√3x+ 4 = 0

​

Answer 1

Answer:

$3x {}^{2} + 4 \sqrt{3} x + 4 = 0 \\ = ( \sqrt{3} x + 2) {}^{2} = 0 \\ = \sqrt{3} x+ 2 = 0 \\ = \sqrt{3} x = - 2 \\ divide \: both \: sides \: by \: \sqrt{3} \\ = \frac{ \sqrt{3} x }{ \sqrt{3} } = \frac{ - 2}{ \sqrt{3} } \\ = 3x = - 2 \sqrt{3} \\ = x = \frac{ - 2 \sqrt{3} }{3} \: \: ans$

Hey! Mate Here is your solution. Thanks