Find the roots of equation 4x2+3x+5=0 (if exists) using the quadratic formula.
Plz answer fast
Answers
Answer:
Given equation
4x
2
+3x+5=0
Dividing by 4
4
4x
2
+
4
3x
+
4
5
=0
x
2
+
4
3x
+
4
5
=0
We know that
(a+b)
2
=a
2
+2ab+b
2
Here a=x
2ab=
4
3x
2b=
4
3
b=
8
3
Adding and subtracting (
8
3
)
2
x
2
+
4
3x
+
4
5
+(
8
3
)
2
−(
8
3
)
2
=0
(x+
8
3
)
2
+
4
5
−(
8
3
)
2
=0
(x+
8
3
)
2
=
64
9
−
4
5
(x+
8
3
)
2
=
64
9−80
(x+
8
3
)
2
=
64
−71
Since square of any number cannot be negative
So, answer does not exist.
Step-by-step explanation:
Note that 4x2 + 3x + 5 = 0 is the same as But (2x+3/4)2 cannot be negative for any real value of x (Why?). So, there is no real value of x satisfying the given equation. Therefore, the given equation has no real roots.Read more on Sarthaks.com - https://www.sarthaks.com/251960/find-the-roots-of-4x-2-3x-5-0-by-the-method-of-completing-the-square