Question

Find the roots of equation by factorisation of (2x-1)(x-3)=(x+5)(x-1)

Answer 1

Answer:

$2x(x - 3) - 1(x - 3) = x(x - 1) + 5(x - 1) \\ \\ 2 {x}^{2} - 6x - x + 3 = {x}^{2} - x + 5x - 5 \ \\ 2{x}^{2} - {x}^{2} - 6x - 5x + 3 + 5 = 0 \\ {x}^{2} - 11x + 8 = 0 \\ by \: using \: quadratic \: formula \\ \\ = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \frac{11 + - \sqrt{121 - 32} }{2} \\ \\ x = \frac{11 + - \sqrt{89} }{2}$