Question

find the roots of equation x^2+4√2x+6 = 0​

Answer 1

Step-by-step explanation:

${x }^{2} + 4 \sqrt{2 } x + 6 = 0 \\ {x }^{2} + 4 \sqrt{2} x = - 6 \\ {x}^{2} + 4 \sqrt{2} x \: + {(2 \sqrt{2) } }^{2} = - 6 + {(2 \sqrt{2} ) }^{2} \\ {(x + 2\sqrt{2}) }^{2} = - 6 + (4 \times 2) = - 6 + 8 \\ {(x + 2 \sqrt{2)} }^{2} =2\\ x + 2 \sqrt{2 } = \sqrt{2} \: or \: - \sqrt{2 } \\ x = \sqrt{2 } - 2 \sqrt{2} = - \sqrt{2} \: \: or \\ x = - \sqrt{2} -2 \sqrt{2} = - 3 \sqrt{2}$

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