Question

Find the roots
of equation
x²-3x-m [m +3] =0
where m
is a constant​

Answer 1

Answer:

you can use

Step-by-step explanation:

x = (-b±√(b²-4ac))/2a

a = 1

here b = -3;

c = -m[m+3]

so it will go as

(3±√(9+4m(m+3)))/2