Find the roots of following equation
i) x2 - 7x+12=0
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Answer:
x^2-7x+12=0
=> x^2-4x-3x+12=0
=> x(x-4)-3(x-4)=0
=> (x-4)(x-3)=0
x-4=0
=> x=4
again, x-3=0
=> x=3
so , x=3 , x=4
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