Find the roots of following equation.....
x+√x-2=4
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Answer:
x + √(x - 2) = 4
√(x - 2) = 4 -x
take square Both sides
x - 2 = 16 -8x + x²
x² -9x +18 = 0
x² -6x -3x +18 =0
x(x -6) -3(x -6) =0
(x -6)(x -3) =0
x = 6 , 3
according to √(x - 2) and (4 -x) ≥0
x≥2 and x ≤4
so, x ≠ 6
only x = 3
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