Question

find the roots of following quadratic eq 2x^2-x+1/8=0,by factorization method ​

Answer 1

Hey buddy here is your answer.

Hope this will help you.
2x^2-x+1/8=0
16x^2-8x+1=0
16x^2-4x-4x+1=0
4x(4x-1) -1(4x-1)=0
(4x-1) (4x-1)
Therefore, x=1/4.

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